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4.9x^2-12.68x-20=0
a = 4.9; b = -12.68; c = -20;
Δ = b2-4ac
Δ = -12.682-4·4.9·(-20)
Δ = 552.7824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12.68)-\sqrt{552.7824}}{2*4.9}=\frac{12.68-\sqrt{552.7824}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12.68)+\sqrt{552.7824}}{2*4.9}=\frac{12.68+\sqrt{552.7824}}{9.8} $
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